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Question

10 mL of a strong acid solution of pH = 2.000 is mixed with 990 mL of another strong acid solution of pH = 4.000. What will be the pH of the resulting solution?
log1.99=0.3

A
4.002
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B
4000
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C
4.2
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D
3.7
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Solution

The correct option is D 3.7
[H+] after mixing 102×10+104×9901000=0.1+0.09901000=0.19901000=1.99×104pH=(log1.99×104)
pH=(4log1.99)
pH=40.3=3.7

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