Question

10 mL of $H_2{O}_2$ solution (volume strength = x) requires 10 mL of N/0.56 $Mn{O}_4^{-}$ solution in acidic medium. Hence x is:

• A. 0.56
• B. 5.6
• C. 0.1
• D. 10

Answer 1

The correct option is D 10

Normality $N_{H_2{O}_2}=\frac{x}{5.6}$
$(V_1{N}_1{)}_{H_2{O}_2}=(V_2{N}_2{)}_{Mn{O}_4^{-}}$
$10\times \frac{x}{5.6}=10\times \frac{1}{0.56}=10mL$