10 mole of ideal gas expand isothermally and reversibly from a pressure of 10 atm to 1 atm at 300 K. What is the largest mass which can lifted through a height of 100 meter?

31842 kg

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58.55 kg

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342.58 kg

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None of these

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Solution

The correct option is B
58.55 kg

$W = - n R T l n \frac{P_{1}}{P_{1}} = - 10 \times 8.314 \times 300 \times 2.303 \times l o g (\frac{10}{1}) = - 57441.42 J$

$W = - m g h$

$m \times 9.81 \times 100 = 57441.42$

$m = 58.55 k g$

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10 mole of ideal gas expands isothermally and reversibly from a pressure of 10 atm to 1 atm at 300 K. What is the heavisest mass which can lifted through a height of 100 meter by this gas?

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. What is the largest mass which can lifted through a height of

100

meter?

Q. 10 mole of ideal gas expand isothermally and reversibly from a pressure of 10 atm to 1 atm at 300 K. What is the largest mass which can be lifted through a height of 100 meter?

5 moles of an ideal gas expand isothermally and reversibly from a pressure of 10 atm to 2 atm at 300k. What is the largest mass which can be lifted through a height of 1 meter in this expansion?

10 mole of ideal gas expands isothermally and reversibly from a pressure of 10 atm to 1 atm at 300 K. What is the heavisest mass which can lifted through a height of 100 meter by this gas?

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10 mole of ideal gas expand isothermally and reversibly from a pressure of 10 atm to 1 atm at 300 K. What is the largest mass which can lifted through a height of 100 meter?

The correct option is B 58.55 kg W = −nRTlnP1P1 = −10 × 8.314 × 300 × 2.303 × log(101) = −57441.42J W = −mgh m × 9.81 × 100 = 57441.42 m = 58.55 kg

The correct option is B
58.55 kg

$W = - n R T l n \frac{P_{1}}{P_{1}} = - 10 \times 8.314 \times 300 \times 2.303 \times l o g (\frac{10}{1}) = - 57441.42 J$

$W = - m g h$

$m \times 9.81 \times 100 = 57441.42$

$m = 58.55 k g$