wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

10 moles of a mixture of hydrogen and oxygen gases at a pressure of 1 atm at constant volume and temperature, react to form 3.6 g of liquid water. The pressure of the resulting mixture will be closest to


A

1.07 atm

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

0.97 atm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

1.02 atm

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

0.92 atm

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

0.97 atm


2H2(g)+O2(g) 2H2O (l )

0.2 mole 0.1 mole 0.2 mole

moles of gas remaining = 9.7 at constant (T) & (V)

n1n2=p1p2

109.7=1p2 & p2=0.97


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Equilibrium Constants
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon