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Question

10 pairs of shoes are there in a closet. Four shoes are selected at random. The probability that there will be at least one pair is

A
224343
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B
1010C4
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C
99323
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D
89323
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Solution

The correct option is C 99323
10 pairs of shoes = 20 shoes
N(4 shoes are selected)= 20C4=4845
P(at least one pair)= 1P(no pair)
N(no pair)= all 4 shoes are from distinct pairs
= 10C4×24=3360
P(no pair)= N(no.pair)N(4.shoes.selected) = 33604845
P(at least one pair)= 133604845
= 14854845
= 99/323

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