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Question

10 L of a monoatomic ideal gas at 0 oC and 10 atm is suddenly released to 1 atm pressure and the gas is expanded adiabatically against the constant pressure. Find the final volume (L) of the gas.

A
54 L
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B
64 L
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C
10 L
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D
61 L
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Solution

The correct option is B 64 L
For an adiabatic process q=0,
From the First law, ΔU=q+w
For an adiabatic irreversible process, w=Pext(V2V1)
w=U=P2V2P1V1γ1
Pext(V2V1) = P2V2P1V1γ1

For a monoatomic gas, γ=1.67

1(V210) = 1×V210×10γ1
10V2 = V21000.67
(10V2)×0.67=(V2100)
V2=63.89 L=64 L

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