$10^{t h}$ term of AP: $2, 7, 12, . . . . .$ is

35

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47

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55

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None of the above

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Solution

The correct option is B $47$
Given $a = 2, d = 12 - 7 = 7 - 2 = 5$
$t_{10} = 2 + (10 - 1) 5 = 47$
Hence, given statement is false.

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Find the $10^{t h}$ term of the AP : 2, 7, 12, . . .

What is the 5th term from the end of the AP 2, 7, 12, ..., 47?

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