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Question

10. y" + 2y' + sin y0

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Solution

The given equation is y''+2y'+siny=0.

ORDER: The order of a differential equation is the order of the highest order derivatives present in the equation.

DEGREE: The degree of a differential equation is the power of the highest order derivatives in the equation.

y''+2y'+siny=0

Thus, the highest order derivative present in the differential equation is y''. Therefore, the order is 2.

The given differential equation is a polynomial equation in y'' and y ' in its derivatives. Thus, the highest power raised is 1.

Hence, its degree is 1 and order is 2.


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