100 200x+100x^2=1 100x^2 200x+99=0 x_1, 2= b±√(b^2 4ac)2a x= ( 200)+√(( 200)^2 4· 100· 99)2· 100= 1110 x= ( 200) √(( 200)^2 4· 100· 99 ...

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Modulus of a Complex Number

100-200x+100x...

Question

$100 - 200 x + 100 x^{2} = 1$ .

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Solution

$100 - 200 x + 100 x^{2} = 1$

$100 x^{2} - 200 x + 99 = 0$

$x_{1, 2} = \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}$

$x = \frac{- (- 200) + \sqrt{{(- 200)}^{2} - 4 \cdot 100 \cdot 99}}{2 \cdot 100} = \frac{11}{10}$

$x = \frac{- (- 200) - \sqrt{{(- 200)}^{2} - 4 \cdot 100 \cdot 99}}{2 \cdot 100} = \frac{9}{10}$

$∴ x = \frac{11}{10}, \frac{9}{10}$

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