Question

# Find it using identity.${\left(104\right)}^{3}$

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Solution

## ${\left(104\right)}^{3}={\left(100+4\right)}^{3}$We know that , ${\left(a+b\right)}^{3}={a}^{3}+{b}^{3}+3{a}^{2}b+3a{b}^{2}$Here , $a=100$ and $b=4.$Substituting the values of a and b we get ,${\left(100+4\right)}^{3}={\left(100\right)}^{3}+{\left(4\right)}^{3}+3×{\left(100\right)}^{2}×4+3×100×{\left(4\right)}^{2}\phantom{\rule{0ex}{0ex}}=1000000+64+3×10000×4+3×100×16\phantom{\rule{0ex}{0ex}}=1000000+64+12×10000+4800\phantom{\rule{0ex}{0ex}}=1000000+64+120000+4800\phantom{\rule{0ex}{0ex}}=1000064+124800\phantom{\rule{0ex}{0ex}}=1124864.$Hence , ${\left(104\right)}^{3}=1124864.$

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