100 cells each of emf 5V and internal resistance 1 - are to be arranged so as to produce maximum current in a 25 - resistance- Each row contains equal number of cells- The number of rows should be

Total no. of cells, = mn = 100 ......(i) Current will be maximum when R=nr/m; 25 = n × 1/m⇒ n = 25 m .......(ii) From equation (i) and (ii) n = 50 and ...

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Byju's Answer

Standard XIII

Physics

Mixed Combination of Cells

100 cells eac...

Question

100 cells each of emf 5V and internal resistance $1 Ω$ are to be arranged so as to produce maximum current in a $25 Ω$ resistance. Each row contains equal number of cells. The number of rows should be

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Solution

The correct option is A 2
Total no. of cells, = mn = 100 ......(i)
Current will be maximum when $R = \frac{n r}{m}; 25 = \frac{n \times 1}{m} \Rightarrow n = 25 m$ .......(ii)
From equation (i) and (ii) n = 50 and m = 2

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100 cells each of emf 5V and internal resistance 1Ω are to be arranged so as to produce maximum current in a 25Ω resistance. Each row contains equal number of cells. The number of rows should be

The correct option is A 2Total no. of cells, = mn = 100 ......(i) Current will be maximum when R=nrm;25=n×1m⇒n=25 m .......(ii) From equation (i) and (ii) n = 50 and m = 2

100 cells each of emf 5V and internal resistance $1 Ω$ are to be arranged so as to produce maximum current in a $25 Ω$ resistance. Each row contains equal number of cells. The number of rows should be

The correct option is A 2
Total no. of cells, = mn = 100 ......(i)
Current will be maximum when $R = \frac{n r}{m}; 25 = \frac{n \times 1}{m} \Rightarrow n = 25 m$ .......(ii)
From equation (i) and (ii) n = 50 and m = 2