Question

$100{cm}^2$ of ${NH}_2$ diffuses through a pin hole in $32.5$ second. How much time will $60cc$ of $N_2$ take to diffuse under same conditions?

Answer 1

$\frac{{\gamma }_{{NH}_3}}{{\gamma }_{N_2}}=\frac{V_{{NH}_3}\cdot t_{N_2}}{t_{{NH}_3}\cdot t_{N_2}}⟹\frac{\sqrt{M_{N_2}}}{\sqrt{M_{{NH}_3}}}=\frac{V_{{NH}_3}\cdot t_{N_2}}{t_{{NH}_3}\cdot t_{N_2}}⟹\frac{\sqrt{28}}{\sqrt{17}}=\frac{100\times t_{N_2}}{32.5\times 60}⟹t_{N_2}=2500.4sec$