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Mole Concept

100 cm3 of a ...

Question

$100 c m^{3}$ of a solution of an acid (molar mass = $98$ ) containing $29.4 g$ of the acid per litre were completely neutralized by $90.0 c m^{3}$ of $a q . N a O H$ containing $20 g$ of $N a O H$ per $500 c m^{3}$ . The basicity of the acid is:

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Solution

Meq of acid $=$ Meq of base
$∴ N_{1} V_{1} = N_{2} V_{2}$
$\frac{29.4}{(\frac{98}{n})} \times 100 = 90 \times (\frac{20}{40} \times \frac{1000}{500})$
$n = 3$ .

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