Question

$100$ $c{m}^3$ of a solution of an acid (molar mass $=98$) containing $29.4g$ of the acid per litre, was completely neutralized by $90.0c{m}^3$ of $aq.NaOH$ containing $20g$ of $NaOH$ per $500c{m}^3$. The basicity of the acid is:

• A. $3$
• B. $2$
• C. $1$
• D. none of the above

Answer 1

Answer: (A)

$3$

m-eq. of acid = m-eq. of base

$\therefore$ $N_1{V}_1=N_2{V}_2$

$\frac{29.4}{\left(\frac{98}{n}\right)}\times 100=90\times (\frac{20}{40}\times \frac{1000}{500})$

$n=3$