Question

$100$ coplanar forces each equal to $10N$ act on a body. Each force makes angle $\pi /50$ with the preceding force. What is the resultant of the forces (in newton)?

Answer 1

Given,$100$ coplanar forces each of $10N$ act on a body, and each force makes angle $\pi /50$ with the preceding force.
So, total angle$=100\times \frac{\pi }{50}=2\pi$
So, these forces make a closed polygon and each force acts opposite to each other.
All the forces will pass through one point and all forces will be balanced, i.e., their resultant will be zero.