100 g of calcium carbonate on treatment with 73g of hydrochloric acid, produces carbon dioxide. What is the volume of carbon dioxide gas produced when the reaction is taking place at STP?
22.4 l
100 g of calcium carbonate = 1 mole of CaCO3
73 g of hydrochloric acid = 2 moles of HCl
CaCO3 + 2HCl→CaCl2 + H2O + CO2
Here, 1 mole of CO2 is produced as a resultant of the above reaction.
At standard temperature and pressure, the volume of solution is always 22.4 litres.