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Molecular Weight of Polymers

100 g of ethy...

Question

$100$ g of ethylene polymerizes to polyethylene according to the equation,
$n C H_{2} = C H_{2} \to - (C H_{2} - C H_{2})_{n} -$
The weight of polyethylene produced will be:

\frac{n}{2}

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100

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\frac{100}{n}

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100

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Solution

The correct option is C $100$ g
During polymerization of ethylene, the mass of reactants and products is same as no reagent is added to ethylene molecule and no byproduct is obtained in the reaction.
Hence, polymerization of $100$ g of ethylene will give $100$ g of polyethylene.

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Similar questions

n C H_{2} = C H_{2} \to (- C H_{2} - C H_{2} -)_{n}

100

100

n C H_{2} = C H_{2} ⟶ - (C H_{2} - C H_{2})_{n} -

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n C H_{2} = C H_{2} \to (C H_{2} - C H_{2})_{n}

n (C H_{2} == C H_{2}) ⟶ - - (- - C H_{2} - - C H_{2} - -) - -_{n}

C == C

C - - C

298 K

+ 590

+ 331 k J m o l^{- 1}

298 K

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