100 kg of Silver has volume $1 m^{3}$ . The density of silver in C.G.S is:

10 {g / c m}^{3}

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0.05 {g / c m}^{3}

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0.1 {g / c m}^{3}

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0.02 {g / c m}^{3}

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Solution

The correct option is C $0.1 {g / c m}^{3}$
Given,

The mass of silver $= 100 k g$

Volume of the cube $= 1 m^{3}$

We know that the density of a substance is given by the following formula

$D e n s i t y = \frac{M a s s}{V o l u m e}$

Density of the silver $= \frac{100}{1} k g / m^{3} = 100 k g / m^{3}$

Now we know that $1 k g = 1000 g m = 10^{3} g m$

and $1 m = 100 c m$

$⟹ 1 m^{3} = 100^{3} c m^{3} = 10^{6} c m^{3}$

Therefore, the density of silver in C.G.S. $= \frac{100 \times 10^{3}}{10^{6}} = 0.1 g m / c m^{3}$

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100 kg of Silver has volume 1m3. The density of silver in C.G.S is:

100 kg of Silver has volume $1 m^{3}$ . The density of silver in C.G.S is: