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Series and Parallel Combination of Resistors

100 mA curren...

Question

100 mA current gives a full-scale deflection in a galvanometer of $2 Ω$ . The resistance connected with the galvanometer to convert it into a voltmeter to measure $5 V$ is

A

98 Ω

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B

52 Ω

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C

50 Ω

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D

48 Ω

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Solution

The correct option is D $48 Ω$
Given, $i_{g} = 0.1 A, R_{g} = 2 Ω$
and resistance added across the galvanometer to convert into voltmeter,
$R_{L} = 5 V$
So, $i_{G} (R_{G} + R_{S}) = R_{L} (i - i_{G}) i_{G} (R_{G} + R_{S}) = 5 V$
$0.1 \times (2 + R_{s}) = 5 (2 + R_{s}) = 50 R_{S} = 48 Ω$

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