Question

100 mA current gives a full scale deflection in a galvanometer of resistance $2\Omega$. The resistance connected with the galvanometer to convert it into a voltmeter of 5 V range is

• A. $98\Omega$
• B. $52\Omega$
• C. $80\Omega$
• D. $48\Omega$

Answer 1

The correct option is D $48\Omega$

$R=\frac{V}{I_g}-G=\frac{5}{100\times {10}^{-3}}-2=50-2=48\Omega$