100 mL of 0.01 M CH3COOH and 200 mL of 0.02 M CH3COONa are mixed to form a buffer solution. 700 mL of water is added to this solution. The pH before and after dilution are:
(pKa = 4.74, log 4 =0.6)
A
5.04,5.04
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B
5.04,0.504
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C
5.34,0.534
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D
5.34,5.34
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Solution
The correct option is D5.34,5.34 Here we are given an acidic buffer. So pH=pKa+log[salt][acid] =4.74+log200×0.02100×0.01 =4.74+log4=5.34
Dilution has no effect on pH of buffer solution, hence pH after dilution will also be 5.34