$100 m l$ of $0.2 M H_{2} S O_{4}$ is added to $100 m l$ of $0.2 M N a O H$ . The resulting solution will be:

A c i d i c

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B a s i c

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N e u t r a l

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S l i g h t l y B a s i c

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Solution

The correct option is A $A c i d i c$
eq.of $0.2 M H_{2} S O_{4} = \frac{2 \times 0.2 M}{1000} \times 100 = 0.04 e q$

eq. of. $0.2 M N a O H = \frac{0.2}{1000} \times 100 = 0.02 e q$

left $[H^{+}] = 0.04 - 0.02 = 0.02$

As $H^{+}$ left in the solution so resultant solution becomes acidic.

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