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Types of Redox Reactions

100 mL of 0...

Question

$100 m L$ of $0.3 N H C l$ were mixed with $200 m L$ of $0.6 N H_{2} S O_{4}$ solution. The final normality of acid was

0.4 N

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0.5 N

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0.6 N

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0.9 N

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Solution

The correct option is C $0.5 N$
$N_{1}, V_{1}$ are normality and volume of $H C l$

$N_{2}, V_{2}$ are normality and volume of $H_{2} S O_{4}$ respectively

$N = \frac{N_{1} V_{1} + N_{2} V_{2}}{V_{1} + V_{2}}$

$N = \frac{0.3 \times 100 + 0.6 \times 200}{100 + 200} = 0.5$ N

Hence, option B is correct

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