Question

$100mL$ of $0.5N$ $NaOH$ were added to $20ml$ of $1N$ $HCl$ and $10mL$ of $3N$ $H_2{SO}_4$. The solution is :

• A. acidic
• B. basic
• C. neutral
• D. none of these

Answer 1

Answer: (A)

acidic

Moles of ${OH}^{(-)}=100\times 0.5\times {10}^{-3}=50$ millimoles

moles of $H^{+}=20\times {10}^{-3}\times 1+10\times {10}^{-3}\times 2\times 3$

$=80$ millimoles

$H^{+}>{OH}^{(-)}$

Hence acidic solution.