Question

100 mL of a 1 M $H_{2}S{O}_4$ solution is diluted with 400 mL of water. Calculate the molarity of the resultant $H_{2}S{O}_4$ solution.

• A. 0.50 M
• B. 0.10 M
• C. 0.01 M
• D. 0.20 M

Answer 1

The correct option is D 0.20 M

$M_1{V}_1=M_2{V}_2$
Where,
$M_1\Rightarrow$ Molarity of the initial solution = 1 M
$V_1\Rightarrow$ Volume of the initial solution = 100 mL
$M_2\Rightarrow$ Molarity of the resultant solution i.e. after dilution
$V_2\Rightarrow$ Volume of the resultant solution = 500 mL
$1\times 100=M_2\times 500$
$M_2=\frac{1\times 100}{500}=0.2M$