100 mL of a gaseous mixture containing CO,CO2 and O2 was sparked; there was contraction of 80 mL volume when the mixture was passed through aqueous caustic potash KOH. The composition of initial gaseous mixture will be respectively :
A
20 mL, 70 mL, 10 mL
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B
50 mL, 30 mL, 20 mL
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C
30 mL, 50 mL, 20 mL
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D
30 mL, 60 mL, 10 mL
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Solution
The correct option is D 30 mL, 60 mL, 10 mL lets first see what happen when gaseous mixture containing CO ,CO2 and O2 was sparked and pass through KOH
i) CO react with O2 to form CO2
2CO +O2→2CO2
ii) KOH absorb the CO2
In option D ,
(i.e 30 mL CO, 60 mL CO2 , 10 mLO2)
20 mL of CO react with 10 mL of O2 to form 20 mL of CO2
but, as already 60 mL of CO2 is present in mixture total amount of CO2 will be 60+20= 80 mL
and thus, when passed through KOH this 80 mL of CO2 will be absorbed