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Question

100 mL of a solution contains 2 g of acetic acid and 3 g of sodium acetate providing Ka=1.8×105. Choose the correct option.

A
This solution is basic in nature
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B
This solution is acidic in nature
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C
This solution is amphoteric in nature
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D
This solution is neutral in nature
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Solution

The correct option is C This solution is acidic in nature
Ka of acetic acid =1.8×105

pKa=log(1.8×105)=4.74

According to Henderson Hasselbalch equation,

pH=logKa+log[Salt][Base]

[Salt]=3×100082×100molL1

[Acid]2×100060×100molL1

pH=log1.8×105+log3×100082×1002×100060×100

pH=4.7851

Therefore, this solution is acidic in nature.

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