Question

$100ml$ of an aqueous solution contains $6.0\times {10}^{21}$ solute molecules. The solution is diluted to $1$ lit. The number of solute molecules present in $10ml$ of the dilute solution is:

• A. $6.0\times {10}^{20}$
• B. $6.0\times {10}^{19}$
• C. $6.0\times {10}^{18}$
• D. $6.0\times {10}^{17}$

Answer 1

The correct option is B $6.0\times {10}^{19}$

100 ml solution diluted to 1 liters (1000) ml contains $6.0\times {10}^{21}$ solute molecular

No of molecules present in 10 ml

$=\frac{10\times 6.0\times {10}^{21}}{1000}=6\times {10}^{19}$