Cathode (RHE) L 2H2O(l)+2e−→H2(g)+2⊖OH(aq)
Anode (LHE) : 2H2O(l)→O2(g)+4H⊕(aq)+4e− In RHE, ⊖OH will be produced which will react with NH⊕4(salt) to form NH4OH(base), causing pOH to decrease or pH to increase.
In LHE, H⊕ will be produced with will react with NH4OH (base)