MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Molarity

100 ml of N...

Question

$100 m l$ of ${N a}_{2} {C O}_{3}$ solution containing $5.3 g$ of ${N a}_{2} {C O}_{3}$ was exactly neutralised by $200 m l$ of $H_{2} {S O}_{4}$ solution. What is the pH of $H_{2} {S O}_{4}$ ?
( $l o g 5 = 0.6990$ )

A

0.5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

0.6990

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

0.3010

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $0.3010$
$H_{2} S O_{4} + N a_{2} C O_{3} \to N a_{2} S O_{4} + H_{2} O + C O_{2}$

mole of $N a_{2} C O_{3} = \frac{5.3}{106} = 0.05$ mole

$0.05 m o l e$ neutralized by $0.05 m o l H_{2} S O_{4}$

Concentration of $H_{2} S O_{4} = \frac{0.05}{0.2 L} = 0.25$

$p H =$ $- l o g [0.25] = 0.6020$

Suggest Corrections

thumbs-up

1

Similar questions

1.25 g

{N a}_{2} {C O}_{3}

{N a}_{2} {S O}_{4}

is dissolved in

250 m l

25 m l

of this solution neutralises

20 m l

0.1 N

H_{2} {S O}_{4}

{N a}_{2} {C O}_{3}

in this sample is:

25 g m

{N a}_{2} {C O}_{3}

{N a}_{2} {S O}_{4}

are dissolved in

250 m l

25 m l

of above solution required

20 m l

0.1 N

H_{2} {S O}_{4}

using phenolphthalein indicator. The mass of

{N a}_{2} {C O}_{3}

in the mixture is:

{N a}_{2} {C O}_{3}

which can be neutralised by 100 ml of 0.05M

H_{2} {S O}_{4}

Q. A solution contain

{N a}_{2} {C O}_{3}

N a H C O_{3}

. 10 ml of this solution required 2.5 ml of 0.1 M

H_{2} {S O}_{4}

for neutralization using phenolphthalein as indicator. Methyl orange is then added when a further 2.5 ml of 0.2 M

H_{2} {S O}_{4}

was required. The amount of

{N a}_{2} {C O}_{3}

N a H C O_{3}

in 1 litre of the solution is ?

Q. The Molarity of

200 m l

H C l

solution which can neutralise

1.6 g

{N a}_{2} {C O}_{3}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Reactions in Solutions

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon