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Question

100th term of the sequence 1, 3, 3, 3, 5, 5, 5, 5, 5, 7, 7, 7, 7, 7, 7, 7...is

A
19
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B
13
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C
17
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D
1
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Solution

The correct option is C 19
1,3,3,3,5,5,5,5,5,7,7,7,7.......1occurs1times3occurs3times5occurs5timesandsoonSo,1+3+5+7+9+11+13+15+17+19=100100thtermis19

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