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Question

100 g of liquid A(molar mass 140 gmol1) was dissolved in 1000 g of liquid B (molar mass 180 gmol1). The vapour pressure of pure liquid B was found to be 500 torr. Calculate the vapour of pure liquid A and its vapour pressure in the solution if the total vapour pressure of the solution is 475 torr.

A
22 torr
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B
32 torr
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C
45 torr
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D
36 torr
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Solution

The correct option is B 32 torr
Given:-
PT=475 Torr, PB=500 Torr
ωA=100 g,MA=140 g;ωB=1000 g,MB=180g

To find:- P0A and PA

nA=100140=57,nB=1000180=509

Now, xA=nAhA+hB=5757+509=0.114

xB=1uA=10.114=0.886

we know, that,

PT=P0AxA+P0BxB

where pAxA=PA and pBxB=PB

Now, P0A×0.114+500×0.886=475

p0A=28070 Torr

PA=pAxA=280.7×0.114

So, PA=31.9998 Torr
or

PA32 Torr
option B is correct

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