Question

$100$ sweets are to be distributed among three friends $A$, $B$ and $C$ in such a way that $B$ gets $10$ sweets more than $A$ and $C$ gets $3$ more than $A$. Find the number of sweets with $A$.

• A. $A=28$ sweets
• B. $A=29$ sweets
• C. $A=30$ sweets
• D. None of the above

Answer 1

Answer: (B)

$A=29$ sweets

$A+B+C=100$

According to the question,
$⟹B=10+A$

$⟹C=3+A$

$\therefore A+10+A+3+A=100$

$⟹3A=100-13$

$⟹A=\frac{87}{3}$

$\therefore A=29$