The correct option is C Normality of OH−=0.05 N and the solution is basic
Milliequivalents of HCl =0.1×100=10
Milliequivalents of NaOH =0.2×100=20
Since the number of equivalents of the base is greater, the solution will be basic.
Number of milliequivalents of OH− left after neutralization = 10
Normality of OH− ions in solution =number of milli-equivalents lefttotal volume of the solution in mL
=10100+100=0.05 N