Question

$100$ tickets are numbered as $00,01,02,.....09,10,11,12,......99$ out of them one ticket is drawn at random. The probability that the product of the digits of the number on the ticket is $0$ is

• A. $\frac{1}{10}$
• B. $\frac{19}{100}$
• C. $\frac{1}{5}$
• D. $\frac{1}{15}$

Answer 1

Answer: (B)

$\frac{19}{100}$

Either first digit is zero or second digit is zero or both zero
No. of such numbers $=9+9+1=19$
$\Rightarrow P=19/100$