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Question

(100×4)+(100×3)=

A
(100×3)+4
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B
100+(4×3)
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C
(100×4)+3
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D
100×(4+3)
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Solution

The correct option is D 100×(4+3)

By distributive property if a, b and c are any three numbers, then

a×(b+c)=(a×b)+(a×c)

(100×4)+(100×3)=100×(4+3)

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