$1000$ N force is required to lift a hook and $10000$ N force is requires to lift a load slowly. Find power required to lift hook with load with speed $v = 0.5 m / s e c$

5 k w

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5.5 k w

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1.5 k w

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4.5 k w

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Solution

The correct option is B $5.5 k w$
$P = F . V = (1000 + 1000) 0.5$
$= \frac{11000}{2} = 5500 = 5.5 k w$

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