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Oxidation Number Method

100ml 0.5N Na...

Question

100ml 0.5N NaOH is mixed in 10ml of 3N H2SO4 and 20 ml of 1N HCl solution. This mixture is not acid and base why?

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100 m L

0.5 N

N a O H

20 m l

1 N

H C l

10 m L

3 N

H_{2} {S O}_{4}

. The solution is :

10 m l

1 N

H C l

25 m l

2 N

H_{2} {S O}_{4}

40 m l

X

N

H {N O}_{3}

are mixed and made up of

2000 m l

100 m l

of this solution required

30 m l

N a O H

taken from a solution containing

4 g

N a O H

250 m l

of solution. What is the value of

X

?

10 m L

10 M

H_{2} S O_{4}

100 m L

1 M

N a O H

are mixed, the resulting solution will be :

Q. An aqueous solution containing

H C l

H_{2} S O_{4}

10

1 N

N a O H

solution for neutralization.

20

ml of the same acid mixture on being treated with an excess of

A g N O_{3}

0.1435

A g C l

. The normality of the

H C l

and the normality of the

H_{2} S O_{4}

are respectively:

Q. 100 mL of 0.5 N NaOH were added to 20 ml of 1N HCI and10 mL of 3N

H_{2} S O_{4}

. The solution is :

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