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Byju's Answer
Standard IX
Chemistry
pH of a Solution
100mL of 0....
Question
100
m
L
of
0.15
M
H
C
l
is mixed with
100
m
L
of
0.005
M
H
C
l
, what is the
p
H
of resulting solution approximately?
A
2.5
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B
1.5
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C
2
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D
1
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Solution
The correct option is
A
2.5
Resultant Molarity
=
M
1
V
1
+
M
2
V
2
V
1
+
V
2
=
(
0.15
)
×
(
100
)
+
(
0.005
)
×
100
200
=
100
[
0.155
]
200
=
0.155
2
=
0.785
⇒
p
H
=
−
log
(
H
+
)
=
−
log
(
0.785
)
=
2.5
Suggest Corrections
0
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