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Byju's Answer
Standard XII
Chemistry
Preparations and Uses of Caustic Soda
100ml of 2M...
Question
100
m
l
of
2
M
H
C
l
solution completely neutralises
10
g
. Of a metal carbonate. Then the equivalent weight of the metal is?
A
50
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B
20
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C
12
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D
100
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Solution
The correct option is
A
50
We know that for
H
C
l
⟶
Molarity= Normality
Gram equivalents of
H
C
l
=
N
o
r
m
a
l
i
t
y
×
V
o
l
u
m
e
=
2
N
×
100
×
10
−
3
=
0.2
e
q
.
After complete neutralisation
Gram equivalent
H
C
l
= Gram equivalents of metal carbonate
Equivalent of metal=
Weight of metal
Gram equivalent of metal
=
10
0.2
=
50
g
m
/
e
q
.
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