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Byju's Answer
Standard XII
Chemistry
Spontaneity
100ml of O2...
Question
100
m
l
of
O
2
gas diffuses in
10
seconds.
100
m
l
of gas
x
diffuses in
t
seconds. Gas
x
and time
t
can be respectively:
A
H
2
,
2.5
seconds
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B
S
O
2
,
16
seconds
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C
C
O
,
10
seconds
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D
H
e
,
4
seconds
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Solution
The correct option is
A
H
2
,
2.5
seconds
If the volume of both the gases are same then,
t
2
t
1
=
√
M
2
M
1
GIven :
t
1
=
10
s
M
1
=
32
g
t
2
=
t
M
2
=
M
Now,
t
10
=
√
M
32
Since two unknowns are present we can substitute the values from the given options and then find the right answer.
For
M
=
2
t
=
2.5
s
e
c
2.5
10
=
√
2
32
1
4
=
√
1
16
1
4
=
1
4
LHS=RHS
Hence, Gas x is
H
2
and time t is
2.5
s
e
c
o
n
d
s
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0
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