Question

${101}^2$ = (using identities)

• A. 10,209
• B. 10,201
• C. 10,401
• D. 10,211

Answer 1

The correct option is B 10,201

Using the identity, $=(a+b{)}^2=a^2+2ab+b^2$, we have
$(101{)}^2$ $=(100+1{)}^2$
$=(100{)}^2+2(100\left)\right(1)+(1{)}^2$
$=10000+200+1$
$=10,201$