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Closure Property

102.If (z-1)/...

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102.If (z-1)/(z+1) is purely an imaginary number then find |z|.

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∣ ∣ ∣ \frac{z}{∣ ∣ ¯ ¯ ¯ z ∣ ∣} - ¯ ¯ ¯ z ∣ ∣ ∣ = 1 + | z |

Then prove that

z

is a purely imaginary number.

\frac{z + 1}{z + i}

is a purely imaginary number; then z lies on a

If $\frac{z - 1}{z + 1}$ is purely imaginary number $(z \neq - 1)$ , find the value of |z|.

z (\neq - 1)

is a complex number such that

\frac{z - 1}{z + 1}

is purely imaginary, then find

| z |

\frac{z - 1}{z + 1}

is purely imaginary number (

z \neq - 1

), find the value of

|z|

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