CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Closure Property

102.If (z-1)/...

Question

102.If (z-1)/(z+1) is purely an imaginary number then find |z|.

Open in App

Solution

Suggest Corrections

thumbs-up

0

Similar questions

∣ ∣ ∣ \frac{z}{∣ ∣ ¯ ¯ ¯ z ∣ ∣} - ¯ ¯ ¯ z ∣ ∣ ∣ = 1 + | z |

Then prove that

z

is a purely imaginary number.

\frac{z + 1}{z + i}

is a purely imaginary number; then z lies on a

If $\frac{z - 1}{z + 1}$ is purely imaginary number $(z \neq - 1)$ , find the value of |z|.

z (\neq - 1)

is a complex number such that

\frac{z - 1}{z + 1}

is purely imaginary, then find

| z |

\frac{z - 1}{z + 1}

is purely imaginary number (

z \neq - 1

), find the value of

|z|

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Closure Property

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Closure Property

Standard VI Mathematics

Join BYJU'S Learning Program

CrossIcon