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Question

103. State the type of reaction taking place. Also balance the equation.

K+H2OKOH+H2


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Solution

Step 1:- List the number of atoms of a different element present in the unbalanced equation

The given chemical equation is as follows:

K+H2OKOH+H2

ElementNumber of atoms in reactantNumber of atoms in product
K11
O11
H23

Step 2:- Start balancing with the compound that contains a maximum number of atoms (reactant or product)

  • In this KOH (Potassium hydroxide) and H2O (Water) has maximum no of the atom and after that check which element has a maximum number of atoms.
  • There is H2O that has a maximum number of atoms. check if it is balanced or not.
  • Start balancing with hydrogen
Atoms of HydrogenIn reactantIn product
Initial(2 in H2O)(1 in KOH) and (2 in H2) = 3
Final (Balanced)2 x (2 in H2O)= 4 hydrogen atoms2 x (1 in KOH)+(2 in H2) =4 hydrogen atoms

Now hydrogen is balanced

Step 3:- Balance the other atoms

  • Potassium is automatically balanced when K is multiplied by 2 in reactant

So, the balanced chemical equation is:

2Kpotassium+2H2OWater2KOHPotassiumhydroxide+H2Hydrogen

Step 4:- Type of reaction reaction

Displacement reaction is the reaction in which more active element displaces a less active element from its compound. So, in the given reaction, Potassium replaced one hydrogen from water and form potassium hydroxide. Thus, the given r4eaction is a displacement reaction.

2Kpotassium+2H2OWater2KOHPotassiumhydroxide+H2Hydrogen (Displacement reaction)


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