104% of 3994 + 48.94% of 1024 =

5000

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4655

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4000

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4900

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None of these

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Solution

The correct option is B
4655

104% of 3994 + 48.94% of 1024 = 4655

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Similar questions

Q. Let A be a non singular, symmetric matrix of order three such that

A = a d j (A + A^{T})

, then

Q. In accordance with the Bohr’s model, find the quantum numberthat characterises the earth’s revolution around the sun in an orbitof radius 1.5 × 1011 m with orbital speed 3 × 104 m/s. (Mass of earth= 6.0 × 1024 kg.)

397 \times 397 + 104 \times 104 + 2 \times 397 \times 104 =

Q. I.

X = (1024)^{\frac{1}{2}}

II.

Y^{2} = 1024

Question 21
The reciprocal of $\frac{- 3}{8} \times (\frac{- 7}{13})$ is
(a) $\frac{104}{21}$
(b) $\frac{- 104}{21}$
(c) $\frac{21}{104}$
(d) $\frac{- 21}{104}$

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104% of 3994 + 48.94% of 1024 =

The correct option is B 4655 104% of 3994 + 48.94% of 1024 = 4655

The correct option is B
4655

104% of 3994 + 48.94% of 1024 = 4655