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106.A spherical surface of radius of curvature R, separates air (refractive index 1.0) from glass (refractive index=1.5) the centre of curvature is in the glass A point object P placed in air is found to have a real image Q in the glass. the line PQ cuts the surface at a point O and PO=OQ.The distance PO is equal to:- 1)5R 2)3R 3)2R 4)1.5R

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Solution

99996113953-0-0

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