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Byju's Answer

Standard XII

Chemistry

Faraday's Second Law

108 g solutio...

Question

108 g solution of $A g N O_{3}$ is electrolysed using $P t$ electrodes by passing a charge of 0.1 F. The mass of the resultant solution left is:

98 g

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107.2 g

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11.6 g

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96.4 g

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Solution

The correct option is D 96.4 g
$A g^{+} + e^{-} \to A g$
$2 O H^{-} \to H_{2} O + 0.5 O_{2} + 2 e^{-}$

Equivalents of $A g^{+}$ lost= $0.1$ = Equivalents of $O_{2}$ formed and escaped

The total mass loss= $0.1 \times 108 + \frac{0.1 \times 32}{4} = 11.6$ g

Therefore, the mass of the solution= $108 - 11.6 = 96.4$ g

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Similar questions

Q. 108 g solution of

A g N O_{3}

is electrolysed using

P t

electrodes by passing a charge of 0.1 F. The mass of the resultant solution left is:

Q. The two aqueous solutions;

A

(A g N O_{3})

and

B (L i C l)

were electrolysed using

P t

electrodes. The pH of the resulting solutions will :

108 g

fairly concentrated solution of

A g N O_{3}

is electrolyzed using

0.1

F of electricity. The weight of resulting solution is: [At. wt of

A g = 108

]

Q. A decinormal solution of

A g N O_{3}

was electrolysed between Pt electrodes. After passing a small current for two hours, a fall of concentration of 0.0005124 equivalent occurred in anodic solution. The mass of copper deposited in copper coulometer placed in series was found to be 0.03879 g. Find the transport number of

N O_{3}^{-}

A g N O_{3}

. Write answer to the nearest integer after multiplying transport number calculated with 10.

When aq. AgNO₃ is electrolysed using Pt electrodes if 3.2 g of O₂ is liberated at the anode, the amount Ag that will be deposited at the cathode in grams is (at wt. of Ag = 108)

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108 g solution of AgNO3 is electrolysed using Pt electrodes by passing a charge of 0.1 F. The mass of the resultant solution left is:

The correct option is D 96.4 gAg++e−→Ag 2OH−→H2O+0.5O2+2e− Equivalents of Ag+ lost= 0.1 = Equivalents of O2 formed and escaped The total mass loss= 0.1×108+0.1×324=11.6 g Therefore, the mass of the solution= 108−11.6=96.4 g

108 g solution of $A g N O_{3}$ is electrolysed using $P t$ electrodes by passing a charge of 0.1 F. The mass of the resultant solution left is: