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Equilibrium Constant from Nernst Equation

10Cl-aq + 2 M...

Question

$10 C l^{-} (a q) + 2 M n O_{4}^{-} (a q) + 16 H^{+} (a q) \to 5 C l_{2} (g) + 2 M n^{2 +} (a q) + 8 H_{2} O (l)$
The value of $E^{o}$ for the above reaction at $25^{o}$ C is 0.15 V. Hence, the value of K for this reaction is :

2.4 \times 10^{25}

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4.9 \times 10^{12}

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1.2 \times 10^{15}

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3.4 \times 10^{20}

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Solution

The correct option is B $2.4 \times 10^{25}$
$E_{c e l l}^{0} = \frac{0.0591}{n} log K_{e q .}$
$0.15 = \frac{0.0591}{10} log K_{e q .}$
$\frac{1.5}{0.0591} = log K_{e q .}$
$log K = 25.38$
$K_{e q} = 2.4 \times 10^{25}$

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