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Standard XII

Chemistry

Percentage Composition

10g of a samp...

Question

$10 g$ of a sample of $B a (O H)_{2}$ is dissolved in $10 m L$ of $0.5 N$ $H C l$ solution. The excess of HCl was titrated with $0.2 N$ $N a O H$ . The volume of $N a O H$ used was $20 c c$ . Calculate the percentage of $B a (O H)_{2}$ in the sample.

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Solution

$B a (O H)_{2} + 2 H C l \to B a C l_{2} + 2 H_{2} O$
Mili equivalents of $H C l$ initially = $5$
Mili eq of NaOH consumed = Mili eq HCl consumed = 4
Mili eq of $H C l$ finally = 1= Mili eq of $B a (O H)_{2}$

Now the wt of $B a (O H)_{2}$ $= \frac{10^{- 3}}{171 \times 2}$
$W t = 3 \times 10^{- 3}$
$% i n s a m p l e \approx .03 %$

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20 g

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10g of a sample of Ba(OH)2 is dissolved in 10mL of 0.5N HCl solution. The excess of HCl was titrated with 0.2N NaOH. The volume of NaOH used was 20cc. Calculate the percentage of Ba(OH)2 in the sample.

Ba(OH)2+2HCl→BaCl2+2H2OMili equivalents of HCl initially = 5Mili eq of NaOH consumed = Mili eq HCl consumed = 4Mili eq of HCl finally = 1= Mili eq of Ba(OH)2Now the wt of Ba(OH)2 =10−3171×2Wt=3×10−3 %insample≈.03%

$10 g$ of a sample of $B a (O H)_{2}$ is dissolved in $10 m L$ of $0.5 N$ $H C l$ solution. The excess of HCl was titrated with $0.2 N$ $N a O H$ . The volume of $N a O H$ used was $20 c c$ . Calculate the percentage of $B a (O H)_{2}$ in the sample.